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06-15-2017 09:08 AM

Hi everyone,

Maybe the answer for my question is obvious but how do I have a distance (mm) for my permanent strain with strain result.

Infact, with the strain equation you have **ε = Δl / l0**. My strain result (Nonlinear Strain - Element Nodal with average) in NX is 0.0036 for one particular node that I chose. So, I have **ε **= 0.0036. How can I find my **Δl **?

l0 is my distance from my node to absolut origin ? I don't understand how convert my strain result in distance.

Thank for in advance for your answer.

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6 REPLIES

Solution

Solution

Accepted by Ganesh_S (Community Manager)

06-29-2017
04:33 PM

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06-15-2017 10:12 AM

The nodal strains would need to be integrated across the elements using shape functions to get the displacements (Δl).

Why don't you obtain the displacements directly from the solution?

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06-15-2017 10:21 AM

Hi JimB,

Thanks for the answer. But how can I obtain directly my displacement ? Because if I use Displacement - Nodal I have my the displacement of my node with the load for the step that I choose. But I would like to obtain my depth in mm of my permanent strain when the load is off.

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06-15-2017 11:21 AM

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06-15-2017 11:31 AM

Thanks, but I work with SOL 601,106 (sorry I should have specify it earlier) because I use 3D contact (only 2 pieces). So create new subcase is not possible. I use a function to applied the load (0s --> 0N to 1s --> 429N).

Do I have to change it to 0s --> 0N , 0.5s --> 429N, 1s -->0N ? The result will be the same ?

Solution

Solution

Accepted by topic author Florianb

06-30-2017
03:13 AM

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06-15-2017 11:50 AM

Yes, in solution 601, you would ramp your loads back down with additional points in the load history curve.

You could do either 0s --> 0N to 1s --> 429N to 2s --> 0N or 0s --> 0N , 0.5s --> 429N, 1s -->0N. There will be no difference if everything is static.

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06-30-2017 03:15 AM

Ok thank you very much for your help

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