Variables using if/then statements

[Co]

Hi guys, 

I try to control the nr of a pattern feature using expressions formula, something like- if length is < or = to 300 the count nr = 3 if length is < = to 400 the count nr = 4 and so on.

If you have any ideas please live a comment, thank you.

[Cesare]

Simply

for one condition      if(A==X)(true)else(false) 

for more                    if(A==X)(true)else(if(B<K)(X1)(true)else(if......))

Ciao

[Co]

Thank you for the fast answer, unfortunately I a totally beginner and I don't understand this coding quite well, I will try to explain it better, so I have a metal bar that has a length of 300, on this bar I want to add pockets as pattern feature and I start from the middle, now what I want is to control the pockets nr by lengthe value, if my length is <= to 300 I want 3 pockets, if length is >300 but <400 I want 4 pockets and if length is >then 400 and <then 500 I want 5 pockets, I hope you anderstand thank you 

[Cesare]

Model the bar, the pocket and the respectives copies.

Suppose p1 is the bar lenght and p2 the number of features copies, you can see this in the expression (ctrl+E).

Then set p2     if(p1<=300)(3)else(if(p1<=400)(4)else(if(p1<=500)(5)else(5)))

(I hope the number of parentheses is correct ;-) )

Ciao

[JohnRBaker]

You could also use a List expressions, particularly if the number of options grows past three or four.

[cowski1]

if(bar_length<400)(3)else(floor(bar_length/100))

The expression above will return 3 if the length is less than 400; otherwise it will return 1 for each 100 units of length.