problem with condition in algorithm

[WD]

Hello everyone

I would like use attached  algorithm in my model. I use this code

if some condition then

    if lastCycle=1 then

         @.move(machine2); 

         lastCycle:=0;

         print lastCycle;

     elseif lastCycle=0 then

          @.move(machine1); 

            lastCycle:=1;

           print lastCycle;

     end;

else

     @.move(machine1)

end;

Is see in consol thet lastCycle is 1, but condition: if lastCycle=1 then, don't execute. Could You help Me?

[Peter]

Hi WD,

maybe the movement was not possible.

Please use the instruction

print @.move(machine2); 

Regards,

Peter

[WD]

Hi,

I try this but nothin is change. Movement is possible, I swapped machine (singProc) on line and problem still exist. I print lastCycle and is 1 all time.

[Peter]

Hi

therefore  it must be the external condition.

Please equip the else-branch with a corresponding print instruction.

When the else-branch is taken the exchange mechanism is not used.

Regards,

Peter

[JiPé]

Hi,

For LastCycle to be always zero, it implies it is not known globally... From my point of view.

So LastCycle must be a variable defined at frame level.

See attached model.

JP

[Peter]

Hello,

yes LastCycle is an object Variable on the toolbox Information Flow.

Sometimes the movement is impossible, like in your model.

The move method has a boolean result. You can use it:

if somecondition.value then
   if lastCycle=1 then
      if @.move(machine2) then
         lastCycle:=0;
         print lastCycle;
      end;
   elseif lastCycle=0 then     

   if @.move(machine1) then
        lastCycle:=1;
        print lastCycle;
      end;
   end;
else
     @.move(machine1)
end; 

[WD]

Hello,

I use a global variable LastCycle and now condition work correctlu.

Thank You for help

WD